4x^2+30x-1350=0

Solution for 4x^2+30x-1350=0 equation:

4x^2+30x-1350=0

a = 4; b = 30; c = -1350;
Δ = b2-4ac
Δ = 302-4·4·(-1350)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-150}{2*4}=\frac{-180}{8}
=-22+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+150}{2*4}=\frac{120}{8}
=15
$